共計 2016 個字符，預計需要花費 6 分鐘才能閱讀完成。

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) = date(時間字段名)

近 30 天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) = date(時間字段名)

本月

SELECT * FROM 表名 WHERE DATE_FORMAT(時間字段名, '%Y%m') = DATE_FORMAT(CURDATE() , '%Y%m' )

上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF(date_format( now() , '%Y%m' ) , date_format(時間字段名, '%Y%m') ) =1

查詢本季度數據

select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());

查詢上季度數據

select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

查詢本年數據

select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());

查詢上年數據

select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

查詢當前這周的數據

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

查詢上周的數據

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

查詢上個月的數據

select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')
select * from user where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ; 
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now()) 
select * from user where MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now()) 
select * from user where YEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = YEAR(now()) and MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now()) 
select * from user where pudate between 上月最后一天 and 下月第一天 

查詢當前月份的數據

select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')

查詢距離當前現在 6 個月的數據

select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

PS: 下面看下 mysql 如何查詢當天信息？

原來不是太熟悉 SQL 查詢語句，什么都是用到了再去查去找，還好網絡提供給我們很多支持。今天又用到了一個語句，一時間真想不出怎么解決，到網上看了看，感覺就有一個，怎么那么簡單啊。需要積累的東西真是太多了。

今天就把我這個簡單的問題記錄下來吧! 算是一個積累：

mysql 查詢當天的所有信息：

select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())

這個有一些繁瑣，還有簡單的寫法：

select * from table where date(regdate) = curdate();

date() 函數獲取日期部分, 扔掉時間部分，然后與當前日期比較即可

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